Panjang balok diketahui adalah √100 , Lebarnya 5² . Jika tinggi balok diketahui 5!! Maka Berapakah Luas permukaan Balok ??
Akun pertamaku terbengkalai
Panjang
√100
10^2/2
10^1
10
__________
Lebar
5²
5 × 5
25
__________
Tinggi
5!!
5 × 3 × 1
5 × 3
15
maka, lp nya yaitu :
2 ( pl + pt + lt )
2 ( 10 ( 25 ) + 10 ( 15 ) + 25 ( 15 ) )
2 ( 250 + 150 + 375 )
2 ( 775 )
1.550 Satuan Luas Permukaan
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SOAL 1
___________________________________________
Panjang
= √100
= √10²
= 10 cm
___________________________________________ Lebar
= 5²
= 5 × 5
= 25 cm
___________________________________________ Tinggi
= 5!!
= 5 × 3 × 1
= 15 × 1
= 15 cm
___________________________________________ Lp Balok = 2 × [PL + PT + LT]
Lp Balok = 2 × [(10 × 25) + (10 × 15) + (25 × 15)]
Lp Balok = 2 × [250 + 150 + 375]
Lp Balok = 2 × [250 + 525]
Lp Balok = 2 × 775
Lp Balok = 1.550 cm²
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